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Seeing gas. Head of ADI s chemistry with solutions: Interconnection of different classes of inorganic speeches Umov set up a siege. twir of reliability

The proponated material presents a methodical distribution of practical robots for the 9th grade: "Decision experimental buildings on the topics "Nitrogen and phosphorus", "The value of mineral goodness", as well as laboratory reports on the topic "Reactions of exchange between electrolytes".

Reactions to the exchange of electrical solutions

methodical distribution to be composed of three parts: theory, workshop, control. In the theoretical part of the guidance of the actions of molecular chemical reactions, Scho protested against the siege, little dissociating speeches, seeing gas. The practical part has established guidelines and recommendations for scientists as to the presentation of laboratory reports. The control is stored from the test plants with the correct vibration.

theory

1. Reactions that lead to a siege.

a) When the sulfate of medi (II) interacts with sodium hydroxide, a blakitny siege of medi (II) hydroxide is formed.

CuSO 4 + 2NaOH = Cu (OH) 2 + Na 2 SO 4.

Cu 2+ + + 2Na + + 2OH - = Cu (OH) 2 + 2Na + +,

Cu 2+ + 2OH - = Cu (OH) 2.

b) In case of interaction of chloride barіyu with sulphate sodium vipadaє bilium milk sludge sulphate barіyu.

Molecular chemistry reactions:

BaCl 2 + Na 2 SO 4 = 2NaCl + BaSO 4.

Outside of that quicker reactionary reactions:

Ba 2 + 2Cl - + 2Na + + = 2Na + + 2Cl - + BaSO 4,

Ba 2 + = BaSO 4.

When carbonate is mixed with sodium bicarbonate (kharchov soda) with hydrochloric acid, it is not easy to boil, or to intensively see bulbs to gas. It can be seen in the carbon dioxide gas CO 2, which makes it cloudy and transparent to the water (calcium hydroxide). Vapnyana water is kalamutnіє, which is why non-perishable calcium carbonate.

a) Na 2 CO 3 + 2HCl = 2NaCl + H 2 O + CO 2;

b) NaHCO 3 + HCl = NaCl + CO 2 + H 2 O;

Ca (OH) 2 + CO 2 = CaCO 3 + H 2 O.

a) 2Na + + + 2H + + 2Cl - = 2Na + + 2Cl - + CO 2 + H 2 O,

2H + = CO 2 + H 2 O;

b) Na + + + H + + Cl - = Na + + Cl - + CO 2 + H 2 O,

H + = CO 2 + H 2 O.

3. Reactions, which are not readily dissociated from the statements.

When sodium hydroxide is combined with calcium and hydrochloric acid or other basic acids in the presence of an indicator phenolphthalein, it is difficult to dissociate in the meadow, as a result of the reaction of neutralization, low-dissociation 2

Molecular analysis of chemical reactions:

a) NaOH + HCl = NaCl + H 2 O;

c) 3KOH + H 3 PO 4 = K 3 PO 4 + 3H 2 O.

Some quick and quick reactions:

a) Na + + OH - + H + + Cl - = Na + + Cl - + H 2 O,

OH - + H + = H 2 O;

b) 2Na + + 2OH - + 2H + + = 2Na + + + 2H 2 O,

2OH - + 2H + = 2H 2 O;

c) 3K + + 3OH - + 3H + + = 3K + + + 3H 2 O,

3OH - + 3H + = 3H 2 O.

Workshop

1. Reactions to exchange between the solutions of electrolytes, so that a siege can be fought against.

a) Carry out the reaction between microsulfate (II) sulphate and sodium hydroxide. Write a molecular, more rapid response to chemical reactions, in addition to signs of a chemical reaction.

b) Carry out the reaction between chlorides and sodium sulfate. Write a molecular, more rapid response to chemical reactions, in addition to signs of a chemical reaction.

2. Reactions, which are taken from gas images.

Carry out reactions between sodium carbonate or sodium bicarbonate (kharchov soda) with hydrochloric or rosaceous acid. See the gas (vikoristovuchi gas-double tube) pass through the hole vapnanu water, poured into the test tube, until it becomes cloudy. Write molecular, quick reference to chemical reactions, in the sense of signs of these reactions.

3. Reactions, which are not readily dissociated from the statements.

Carry out the reaction of neutralization in the meadow (NaOH or KOH) and acid (HCl, HNO 3 or H 2 SO 4), in front of the distribution of phenolphthalein in the meadow. In addition, it is important to be careful about writing molecular reactions, because of the speedy reactions of chemistry.

signs, With the help of the given reactions, it is possible to vibrate from the offensive turn:

1) seeing bulbs to gas; 2) vipadannya siege; 3) scent; 4) deciding the siege; 5) heat vision; 6) change to color.

Control (test)

1. Ionne ryvnyannya reaction, in which a black siege takes place, - tse:

a) Cu 2 + 2OH - = Cu (OH) 2;

c) Fe 3+ + 3OH - = Fe (OH) 3;

d) Al 3+ + 3OH - = Al (OH) 3.

2. Ionne reasonable reaction, in which carbon dioxide is seen, - tse:

a) CaCO 3 + CO 2 + H 2 O = Ca 2+ +;

b) 2H + + SO 2 3 = H 2 O + SO 2;

c) CO 2 3 + 2H + = CO 2 + H 2 O;

d) 2H + + 2OH - = 2H 2 O.

3. Ionne rivnyannya reactions, in which low-dissociating speeches take root, - tse:

a) Ag + + Cl - = AgCl;

b) OH - + H + = H 2 O;

c) Zn + 2H + = Zn 2+ + H 2;

d) Fe 3+ + 3OH - = Fe (OH) 3.

4. Ionne equal reaction, in which sieges are set up, - tse:

a) Cu 2 + 2OH - = Cu (OH) 2;

b) CuO + 2H + = Cu 2+ + H 2 O;

c) Fe 3+ + 3OH - = Fe (OH) 3;

d) Ba 2 + SO 2 4 = BaSO 4.

5. Molecular equivalence, which is similar to the rapid ionic reaction 3OH - + 3H + = 3H 2 O, - tse:

a) NaOH + HCl = NaCl + H 2 O;

b) 2NaOH + H 2 SO 4 = Na 2 SO 4 + 2H 2 O;

c) 3KOH + H 3 PO 4 = K 3 PO 4 + 3H 2 O;

d) Ba (OH) 2 + 2HCl = BaCl 2 + H 2 O.

6. Molecular Equivalence, which is indicative of a speedy ionic reaction

H + + = H 2 O + CO 2, -

a) MgCO 3 + 2HCl = MgCl 2 + CO 2 + H 2 O;

b) Na 2 CO 3 + 2HCl = 2NaCl + CO 2 + H 2 O;

c) NaHCO 3 + HCl = NaCl + CO 2 + H 2 O;

d) Ca (OH) 2 + CO 2 = CaCO 3 + H 2 O.

Відповіді. 1 -a; 2 -v; 3 -b; 4 -R; 5 -v; 6 -v.

Decision of experimental plants on the topic "Nitrogen and phosphorus"

When researching new material on the topic of "Nitrogen and Phosphorus", a number of preliminaries can be seen about how to reject amyaku, name nitrates, phosphates, ammonium salts, fill up singing tips and remember. At the time of methodical development, a number of buildings have been established. For the viconannya practical robots finish three works: one - on the rejection of the speech, two - on the basis of the speech. With practical robots, it is possible for the scientists to proponate the form in order to lie down on the formalized sound (div. Zavdannya 1, 2). (Guidelines for the reader.)

Zavdannya 1

Take a note of it and make it clear.

a) Rejecting amiaku.

Summing up the portions of solid ammonium chloride and calcium hydroxide powder, heat it in a sample from a gas-double tube. Whenever there will be an amiak, which needs to be taken into a dry test tube, roasted with a opening ... ......... ( why?).

Write a ryvnyannya reaction to reject amiaku.

…………………………………………………..

b) The value of the amiaku.

It can be seen by smell ............ (Name of the speech), And also according to the color of the litmus or phenolphthalein. When detecting amiaku in water, set up ....... (Name of submission) Tom litmus papіrets. ....... (Show color), And barless phenolphthalein becomes ............. (Show color).

Change the points to insert words behind the zmist. Write a simple reaction.

…………………………………………………..

* Amiaku smell of liquid ammonia in the home pharmacy. - Approx. ed.

zavdannya 2

Otrimate nitrate in two different ways, in the presence of an onset of speech: concentrated nitric acid, shavings, midi (II) sulfate, sodium hydroxide. Write an example of chemistry reactions in molecular view, in terms of change. In the 1st method, for an oxidation-specific reaction, write an analogy to the electronic balance, but rather an oxidation and a reference. In the second method, write the quickest reactionary reactions.

1st z p about with about b. Micron + nitric acid. Slightly heated instead of test tubes. Bezbarvny razchin st ... .. (Show color) That is why he pretends ... .. (Name of the speech); gas is seen ... ... with an unacceptable smell, the price - ... (Name of the speech).

2nd z p about with about b. When sulphate of medi (II) is combined with sodium hydroxide, siege ... .. (Name of the speech)... Do not add nitric acid until the siege is relieved again ......... (Name the siege)... To pretend to be a glimpse of blakitny razchin ...... (Name solі).

zavdannya 3

Bring in the old way that the ammonium sulfate contains NH 4 + and SO 2 to the warehouse.

zavdannya 4

What is the significance of the difference between sodium orthophosphate, sodium chloride, sodium nitrate in test tubes No. 1, No. 2, No. 3? For the sake of caution, write the molecular and rapid reaction times.

zavdannya 5

Mayuchi words: nitric acid, shavings or shavings, etc. Write a summary of the dissociation of nitric acid; molecular level for the reaction of medium with concentrated nitric acid and equal to the electronic balance, especially oxidizing and leading.

zavdannya 6

Separate the solution to nitrate by different methods, such as: nitric acid, oxide of midi, basic carbonate of midi and carbonate of hydroxomed (II). Write down the molecular reactions that are quicker and more accurate. Introduce the signs of chemical reactions.

control tests

1. Introduce rivnyannya reaction, de vipada zhovty siege.

2.Ionny rivnyannya reaction, in yakiyuyutsya biliy sirnisty siege, - tse:

3. To prove the presence of nitrate-ion in nitrate, take:

a) hydrochloric acid і zinc;

b) sirchan acid and sodium chloride;

c) sirchan acid and honey.

4. Reagent for chloride-ion є:

a) honey and sirchan acid;

b) nitrate of the medium;

c) chloride bar.

5. At the reactionary reaction, the scheme of

HNO 3 + Cu -> Cu (NO 3) 2 + NO 2 + H 2 O,

before oxidizing the demand, put a factor:

a) 2; b) 4; about 6.

6. The main and acidic salts are suitable for couples:

a) Cu (OH) 2, Mg (HCO 3) 2;

b) Cu (NO 3) 2, HNO 3;

c) 2 CO 3, Ca (HCO 3) 2.

Відповіді. 1 -a; 2 -b; 3 -v; 4 -b; 5 -b; 6 -v.

The value of mineral goodness

Methodical development of the whole practical robot consists of three parts: theory, workshop, control. In the theoretical part of the data of outward views, according to the distinctive designation of cations and anions, they enter the warehouse of mineral good. At the workshop, the butts of seven mineral goodies with a description їх characteristic signs, And also the dictionaries of yakisnykh reactions. In the text, replace the specks and the sign of nutrition, insert the ones that come after the change. For the visitor of a practical robot, the reader will be asked to take a chotiri dobriva. The control of the knowledge of scientists is stored from test plants according to the value of the formulas of good, such as data in the whole practical robot.

theory

1. A reagent for chloride-ion є nitrate of the medium. Reactions go to the statements of a white curdled siege:

Ag + + Cl - = AgCl.

2. Ion Amonia can be found behind a help meadow. When heating the range of ammonia salts in a wide meadow, you can see amiak, a slight characteristic smell:

NH + 4 + OH - = NH 3 + H 2 O.

It is also possible to make a name for Amonia by speeding up with water soaked in red litmus papier, a universal indicator or a phenolphthaleine brown paper. The father of the treasure is rubbed over the vapors, which can be seen from the test tubes. Chervony litmus is blue, the universal indicator is violet, and phenolphthalein is raspberry.

3. To make the nitrates-ions to the size of the salt, add shavings, or some small pieces, then add the concentrated acid and heat. After a dozen hour, you can see the gas from the brown collar with an unacceptable smell. The vision of brown gas NO 2 depends on the presence of ions.

for example:

NaNO 3 + H 2 SO 4 NaHSO 4 + HNO 3,

4HNO 3 + Cu = Cu (NO 3) 2 + 2NO 2 + 2H 2 O.

4. A reagent for phosphate-ion є nitrate of the medium. When it is added to the level of the phosphate of the vipadan of the sediments of the phosphate of the medium:

3Ag + + PO 3 4 = Ag 3 PO 4.

5. Reagent for sulfate-ion є chloride bar. Vipadak bilium milk sludge to sulphate bariiu, non-reactive in oztovic acid:

Ba 2 + SO 2 4 = BaSO 4.

Workshop

1. Sylvinite (NaCl KCl), rhizome crystals, the difference in water is good. Half an 'I get lost in a zhovty colir. When looking halfway through the blue side, it’s like a photo of the barn. Z ...... .. (Name the reagent) yes, the siege of siege ... (Name solі).

KCl +? -> KNO 3 + AgCl.

2. Ammonium nitrate NH 4 NO 3, or ...... .. (The name is kind), Bily crystals, good luck by the water. With sirchanoy acid and I see a storm of gas ... (Name of the speech)... Out of reach ....... (Name the reagent) when heated, you see the smell of amiaku;

NH 4 NO 3 + H 2 SO 4 NH 4 HSO 4 + HNO 3,

HNO 3 + Cu -> Cu (NO 3) 2 +? +? ...

NH 4 NO 3 +? -> NH 3 + H 2 O + NaNO 3.

3. Calcium nitrate (KNO 3), or ... (The name is kind), З H 2 SO 4 і ......... (Name of the speech) yes storm gas. Half-I'm getting into the violet color.

KNO 3 + H 2 SO 4 KHSO 4 + HNO 3,

4HNO 3 +? -> Cu (NO 3) 2 +? + 2H 2 O.

4. Ammonium chloride NH 4 Cl with range ....... (Name the reagent) when heating the amiak, put a red litmus in a blue color. Z ...... (Name of anion to reagent) srіbla yes bіliy sirnisty siege ... (Name the siege).

NH 4 Cl +? = NH 4 NO 3 + AgCl,

NH 4 Cl +? = NH 3 + H 2 O + NaCl.

5. Ammonium sulfate (NH 4) 2 SO 4 with a range of ammonium when heated, put a red litmus in a blue color. Z ...... .. (Name the reagent) yes, the billy milk siege ... ... (Name the siege).

(NH 4) 2 SO 4 + 2NaOH = 2NH 3 + 2H 2 O +? ,

(NH 4) 2 SO 4 +? -> NH 4 Cl +? ...

6. Sodium nitrate NaNO 3, or ...... (The name is kind), Bili crystals, the separation in water is good, with H 2 SO 4 and Cu and gas storms. Half an 'I get lost in a zhovty colir.

NaNO 3 + H 2 SO 4 NaHSO 4 +? ,

Cu -> Cu (NO 3) 2 +? + 2H 2 O.

7. Calcium dihydrogen phosphate Ca (H 2 PO 4) 2, or ... (The name is kind), Syriy fine-grained powder or granules, disgustingly razchinyatsya in the water, s ... .. (Name the reagent) yes ... .. (order kolіr) sieges ......... (Name of the speech) AgH 2 PO 4.

Ca (H 2 PO 4) 2 +? -> 2AgH 2 PO 4 + Ca (NO 3) 2.

Control (test)

1. Rozhevi crystals, good luck near the water, drive halfway into the zhovty color; in case of interaction with AgNO 3 vipadaє siege - tse:

a) Ca (H 2 PO 4) 2; b) NaCl KCl;

c) KNO 3; d) NH 4 Cl.

2. Kristali is kindly out of the water; in the reaction with H 2 SO 4 and I see a storm of gas, in a gap in the meadow when heated, give amiak, if you put a red litmus in a blue color, - tse:

a) NaNO 3; b) (NH 4) 2 SO 4;

c) NH 4 NO 3; d) KNO 3.

3. Light crystals, kindly at the water; during the interaction of H 2 SO 4 and Cu, a storm gas is seen; half of the bar is in the violet color - tse:

a) KNO 3; b) NH 4 H 2 PO 4;

c) Ca (H 2 PO 4) 2 CaSO 4; d) NH 4 NO 3.

4. Kristali is kindly out of the water; with the nitrate of the medium, yes, the sieges, with the meadow when heating, yes the amiak, betting on the red litmus in the blue color, - tse:

a) (NH 4) 2 SO 4; b) NH 4 H 2 PO 4;

c) NaCl KCl; d) NH 4 Cl.

5. Light crystals, good luck near the water; s BaCl 2 yes a lactic siege, with a meadow yes amiak, bet that you can bar a red litmus in a blue color, - tse:

c) NH 4 Cl; d) NH 4 H 2 PO 4.

6. Light crystals, good luck near the water; with the interaction of H 2 SO 4 і Cu yes, the storm gas, half the barring in the zhovtiy kolіr - tse:

a) NH 4 NO 3; b) (NH 4) 2 SO 4;

c) KNO 3; d) NaNO 3.

7. Syria fine-grained powder abo granules, the degree of dispersion in the water of the trash, with the degree of nitrate of the medium, even the most sieges:

a) (NH 4) 2 SO 4; b) NaCl KCl;

c) Ca (H 2 PO 4) 2; d) KNO 3.

Відповіді. 1 -b; 2 -v; 3 -a; 4 -R; 5 -b; 6 -R; 7 -v.

In a test tube with a solution of salt X, a solution was given to the speech Y. The result was a reaction, I can describe the coming sooner rather than later S 2 + 2H + = H 2 S.

1) sodium sulfide;

2) vugic acid;

3) chlorine day;

4) sulfide zaliza (II);

5) calium sulfite;

At the test tube with the solution of the salt X, they gave the answer to the U.

1) calcium nitrate;

2) chloride bar;

H) hydrochloric acid;

4) calcium carbonate;

5) sirchan acid;

Write down in the table the numbers of the addresses given in all letters.

In a test tube with a range of sodium salt X, they gave the answer to U.

S 2+ Fe 2+ = FeS.

From the proponents of the change of speech X and Y, which can enter into the described reaction.

1) sodium sulfide;

2) sodium sulfite;

3) sirvodden;

4) hydroxide zaliz (II);

5) sulfate of zaliz (II);

Write down in the table the numbers of the addresses given in all letters.

In a test tube with a salt solution, X was given a U. From the proponents of the change of speech X and Y, which can enter into the described reaction.

1) calcium sulfite;

2) sodium hydroxide;

H) sulfate of zaliz (II);

4) chlorine day;

5) sodium nitrate.

Write down in the table the numbers of the addresses given in all letters.

At the test tube with the range of the speech, X was given the acidity and U.

From the proponents of the change of speech X and Y, which can enter into the described reaction.

1) sodium sulfide;

2) vugic acid;

3) sirchan acid;

4) hydroxide barium;

5) calcium hydroxide.

Write down in the table the numbers of the addresses given in all letters.

At the test tube with the solution of the speech, X was given the solution of the salt U. From the proponents of the change of speech X and Y, which can enter into the described reaction.

1) sulfate of zaliz (II);

2) hydrochloric acid;

3) sodium hydroxide;

4) calcium nitrate;

5) sulphate mіdі (II).

Write down in the table the numbers of the addresses given in all letters.

At the test tube with a firm, unreliable at the water with a speech, X was given a breakdown of the speech of U. From the proponents of the change of speech X and Y, which can enter into the described reaction.

1) calcium carbonate;

2) sodium hydroxide;

H) sulfate barіyu;

4) sirchan acid;

5) oxide midi (II).

Write down in the table the numbers of the addresses given in all letters.

At the test tube with the range of the speech, X was given the solution of the salt Y. The result was a reaction, I would describe it as soon as possible: CO 3 2- + 2H + = H 2 O + CO 2.

From the proponents of the change of speech, X and Y. can enter into the described reaction.

1) calcium hydrocarbonate;

2) calcium hydroxide;

3) restic acid;

4) sirchan acid;

5) sodium carbonate.

Write down in the table the numbers of the addresses given in all letters.

At the test tube with the solution of the speech, X was given the solution of the salt U. From the proponents of the change of speech X and Y, which can enter into the described reaction.

1) chloride mіdі (II);

2) hydrochloric acid;

3) sodium hydroxide;

4) sodium nitrate;

5) zaliza sulfate (III).

Write down in the table the numbers of the addresses given in all letters.

In a test tube with a range of acid, X gave a solution to the problem of U.

From the proponents of the change of speech X and Y, which can enter into the described reaction.

1) potassium sulfate;

2) hydrohydric acid;

3) sirchan acid;

4) ammonium sulfide;

5) sodium sulfite.

Write down in the table the numbers of the addresses given in all letters.

Zinc was recovered in concentrated form with sodium hydroxide. Having pretended to have a glimpse of the differences of speech, X was viparized, and then fried. At the same time, a firm speech Y was established. From the proponated transcript of the vibration of the speech X and Y, as we will suggest we will describe it.

1) Na 2 ZnO 2;

2) Zn (OH) 2;

3) ZnO;

4) Na 2;

5) NaOH.

Write down in the table the numbers of the addresses given in all letters.

The amount of sodium chloride was compromised by the amount of salt X. The amount of precipitation was broken, the amount of dry wine was cooked for the next meal, when a barless gas was seen Y.

1) AgNO 3;

2) HNO 3;

3) Na 2 CO 3;

4) CO 2;

5) O 2.

Write down in the table the numbers of the addresses given in all letters.

Aluminum nitrate was fried. Otrimane, as a result of a solid speech, X was fused with too much calcium hydroxide. Otrimaniy melted over too much water, at the same time they got a glimpse of the differences between the words of Y.

1) Al;

2) Al 2 O 3;

3) KAlO 2;

4) K;

5) K 3 AlO 3.

Write down in the table the numbers of the addresses given in all letters.

Hydroxide of zaliza (II) was reversed with peroxide. Otrimane Storm River X was fused with solid calcium hydroxide. Otrimaniy float, to take revenge on the power of Y, they chipped over too much water, as a result of which they rejected the storm of speeches X.

1) Fe 2 O 3;

2) Fe (OH) 3;

3) KFeO 2;

4) FeO;

5) K 3 FeO 3;

Write down in the table the numbers of the addresses given in all letters.

Aluminum hydroxide was fused with calcium hydroxide. Otrimanu sil X was chilled with too much hydrochloric acid, at the same time the speech of Y was approved.

1) K;

2) KAlO 2;

3) K 3 AlO 3;

4) AlCl 3;

5) Al (ClO 4) 3;

Write down in the table the numbers of the addresses given in all letters.

Calcium sulfite was treated with hydrochloric acid. Otrimany gas X was poured over too much calcium hydroxide, at the same time the speech Y was approved.

1) H 2 S;

2) CaS;

3) Ca (HSO 3) 2;

4) SO 2;

5) CaSO 3.

Write down in the table the numbers of the addresses given in all letters.

In one of the test tubes with the siege, the aluminum hydroxide was given a strong acid X, and in the first one - the solution Y. From the proponents of the change of speech X and Y, which can enter into the description of the reaction.

1) hydrobromic acid;

2) sodium hydrosulfide;

3) hydrohydric acid;

4) calium hydroxide;

5) ammonium hydroxide.

Write down in the table the numbers of the addresses given in all letters.

Nitrat siribla fried. Until a solid surplus of X was established, concentrated nitric acid was added, at the same time, the intensively visible gas Y was promoted.

1) oxide of medium (I);

2) nitrite of the medium;

3) average;

4) nitrogen oxide (II);

5) nitrogen (IV) oxide.

Write down in the table the numbers of the addresses given in all letters.

The bromide of the medium was heated with zinc powder. Otriman was smashed by the water. Having established the razchin on the spots, the razchin was added to the hydroxide of calium. Some of the evidence of the strong siege of X was considered, and then, when a new port was added, the amount of hydroxide of calium was added - the third, according to the statements made by Y.

1) Ag;

2) ZnBr 2;

3) Zn (OH) 2;

4) K 2 ZnO 2;

5) K 2.

Write down in the table the numbers of the addresses given in all letters.

Phosphorus (V) chloride was added to the excess amount of hydroxide bar. After the siege of X, they hung up and fried it and fried it, and at the same time, the speech of Y was approved.

1) Ba 3 (PO 4) 2;

2) BaHPO 4;

3) BaCl 2;

4) CO 2;

5) CO.

Write down in the table the numbers of the addresses given in all letters.

Sodium dichromate was reacted with sodium hydroxide. Otriman's speech X was sprinkled with sirchan acid, from the point of view, then, having pretended to, they saw the river Y of orange color. From the proponents of the change of speech X and Y, as it appears, we will describe it.

1) Na 2 Cr 2 O 7;

2) Na 2 CrO 4;

3) NaCrO 2;

4) Na 3;

5) Na 2 SO 4.

Write down in the table the numbers of the addresses given in all letters.

Sulfate mіdі (II) was added to the level of chloride barіu. Vipav sieges X vidfiltruvali. Iodide was added to the point of view before it was overwhelmed; From the proponated transference to the vibration of the speech X and Y, as we will guide the description.

1) BaSO 3;

2) BaSO 4;

3) CuI 2;

4) CuI;

5) KCl;

Write down in the table the numbers of the addresses given in all letters.

At the test tube in the range of the meadow (speech X), they gave the solution to the speech Y. The result was a reaction, which I can describe as soon as possible OH - + H + = H 2 O.

1) calium sulfide;

2) vugic acid;

3) sirchan acid;

4) hydroxide barium;

5) sodium hydroxide.

Write down in the table the numbers of the addresses given in all letters.

As a result of the change in the development of sulphate of medi (II) with the salt, X was set. The tsiu sil was heated with concentrated strong acid, as a result of which a new syl Y was established.

1) FeS;

2) CuS;

3) FeSO 4;

4) FeSO 3;

5) Fe 2 (SO 4) 3.

Write down in the table the numbers of the addresses given in all letters.

Before the breakdown of chloride zaliz (III), the tide of breakdowns of sodium sulfide, as a result of the siege. On the removal of the siege, they decided to use a solution of sirchanoic acid, while the siege of X was resolved. The undissolved part of the siege of Y is small. From the proponated transference to the vibration of the speech X and Y, as we will guide the description.

1) FeS;

2) Fe (OH) 2;

3) Fe 2 S 3;

4) S;

5) Fe (OH) 3.

Write down in the table the numbers of the addresses given in all letters.

Chloride of zaliza (III) was added to the solution with sodium hydroxide, during the whole period of precipitation of X. The precipitation was reduced and reduced in hydrochloric acid. At the same time, the speech of Y was approved. From the proponated transcription of the speech of X and Y, as it is suggested, we will guide the description.

1) Fe (OH) 2;

2) Fe (OH) 3;

3) FeI 3;

4) I 2;

5) NaCl;

Write down in the table the numbers of the addresses given in all letters.

An excess of carbon dioxide was passed through the solution with sodium hydroxide. Otriman at the end of his speech, X was seen from the point of view, hung and fried. At the same time, a firm speech Y has been established. From the proponated translation of the vibration of the speech X and Y, as we will be able to guide the description.

1) Na 2 CO 3;

2) NaHCO 3;

3) HCOONa;

4) Na 2 O 2;

5) Na 2 O.

Write down in the table the numbers of the addresses given in all letters.

Speech X was added to one test tube with a solution of medi (II) chloride, and as a result of the reaction, the siege of the Chervony Colora was fostered. In the first test tube with the solution, the medi (II) chloride was given a solution to the problem of Y. The result of the reaction showed an intrinsic strength. From the proponents of the change of speech X and Y, which can enter into the description of the reaction.

1) zinc;

2) zinc oxide;

3) calium bromide;

4) fluoride of the medium;

5) average.

Write down in the table the numbers of the addresses given in all letters.

In one of the test tubes, the sulphate of zaliz (III) was given a splinter of drops at the level of salt X, and in one test tube - at the level of Y. From the proponents of the change of speech X and Y, which can enter into the description of the reaction.

1) BaCl 2;

2) NH 3;

3) Cu (OH) 2;

4) K 2 CO 3;

5) AgNO 3;

Write down in the table the numbers of the addresses given in all letters.

Up to one of the test tubes with hydrochloric acid, a solution was given to the range of salt X, and to the bottom of the test tube, Y. The results in the skin of the test tubes showed the appearance of a barless, odorless gas. From the proponents of the change of speech X and Y, which can enter into the description of the reaction.

The head for self-revision є with a general mind for mastering the material, before the skin section, tests are done on the passed topics, as it is necessary to virishity.
Having connected all the work with the distribution, you will improve your result and you will be able to wonder about the results to all the applications, but in addition to the intelligence you have made some pardons, if your knowledge needs to be noticed!
The test is 10 tests of test 8, part 1 of EDI, which can be changed in the same rank, and taken from our established basis of nutrition!
Try to get rid of 90% of the current views, so we will be able to sing in your knowledge!

If you are engaged with a tutor, then writing on the cob of dough is real! Pay your credit to your name, the tutor knows you have passed the test, look at your mercy and vrakhu your glazes and memorize them!

corrode only additional material We will present it below, if you want to revise the enclosed material!
After passing the dough, wondering about the food before the meal was pardoned and closing the material before the repeated passing!

Dovidkovy material for passing the test:

Mendelian table

Distinction table

Typical food that you can learn in this test (see the food and be sure you know you can be surprised if you passed the test until the end of the day.

At the test tube with the solution of the salt X, they gave the solution to the speech Y. The result was a reaction, I will describe it as soon as possible. From the proponents of the change of speech X and Y, which can enter into the described reaction.
At the test tube with the solution of the salt X, they gave the solution to the speech Y. From the proponents of the change of speech X and Y, which can enter into the described reaction.
At the test tube with the size of the salt of the calories X, they gave the solution to the speech Y. The result was a reaction, I will describe the coming sooner than later: ____. From the proponents of the change of speech X and Y, which can enter into the described reaction.
At the test tube with the solution of the salt X, the solution was given to the solution Y. At the result of the reaction, the appearance of the barless gas was deteriorated. From the proponents of the change of speech X and Y, which can enter into the described reaction.
At the test tube with the range of speech, X was given the range of acid and Y. The result was a reaction, I will describe it as soon as possible: ____. From the proponents of the change of speech X and Y, which can enter into the described reaction.
At the test tube with the solution of the word X, the solution of the salt Y was added. The result of the reaction was the result of the blakite siege. From the proponents of the change of speech X and Y, which can enter into the described reaction.
At the test tube with a solid speechless at the water, X was given a breakdown of the speech Y. From the proponents of the change of speech X and Y, which can enter into the described reaction.
At the test tube with the range of speech X, they added the range of salt Y. The result was a reaction, I will describe it as soon as possible: ____. From the proponents of the change of speech X and Y, which can enter into the described reaction.
At the test tube with the resolution of the speech, X added the solution to the salt Y. From the proponents of the change of speech X and Y, which can enter into the described reaction.
At the test tube with the range of acid, X was given a solution to the problem of Y. The result was a reaction, which I would describe as soon as possible. From the proponents of the change of speech X and Y, which can enter into the described reaction.

Solution of tasks of part C2

1. The sum of two gases, as they do not show the color and smell of A and B, were missed when heating over the catalyst, so that they could take revenge. Approvals gas U missed in the range of hydrobromic acid, became a reaction of neutralization. The amount of vapors was dispensed and the surplus was heated with dry feces, as a result, a barless gas was seen with a pungent odor. When gas B is burned, water and gas A are set on the turn. Write a description of the reactions.

Decision

It is possible to neutralize acid breakdowns by speech, which is the main power. So, as when the reaction product is heated with liquid calories, a gas with a pungent smell and gas, which is the main power, is seen, then the gas is ammonium NH 3.

1 іvnyannya - synthesis of ammonia from nitrogen and water;

2 rivnyannya - acid neutralization;

3 rіvnyаnnya - yakісna reaction to amіak in the meadow;

4 rivnyannya - mines amiaku at every turn, when you see nitrogen

Gazi - N 2, H 2 і NH 3.

1) N 2 + 3H 2 ↔ 2NH 3

2) NH 3 + HBr = NH 4 Br

3) NH 4 Br + KOH = KBr + H 2 O + NH 3

4) 4NH 3 + 3O 2 = 2N 2 + 6 H 2 O

2. Clean gas is permeable to water peroxide. They boiled water and added magnesium shavings to the excess. The gas was passed through the line of copper sulfate. After the siege of the Black Sea region, they drove and went to the sea. Write a description of the reactions.

Decision

In the clean gas, the steps of the oxidized water are +4. Otzhe, vіn can be both oxidizing, and a forerunner. With a strong oxidation of the oil, it will be the forerunner and increase the oxidation step to +6 (in order to pretend to be H 2 SO 4) (1 equal).

Pislya viparuvannya H 2 O asserts, concentrated sirchan acid, yaka, together with Mg (active metal) give sirkowen (2). Sulfate mіdі - II, reacting with water, give sulphid mіdі - sedimentary color (3). In the case of vialing of sulfides, serum oxide (IV) and metal oxide (4) are formed.

1) SO 2 + H 2 O 2 = H 2 SO 4

2) 5H 2 SO 4 conc. + 4Mg = 4MgSO 4 + H 2 S + 4H 2 O

3) H 2 S + CuSO 4 = CuS ↓ + H 2 SO 4

4) 2CuS + 3O 2 = 2CuO + 2SO 2

3. When vipalyuvanny deyakogo mineral A, it is stored in 2 elements, gas, like a slight odor and sane bromine water with solutions in the range of two strong acids. In case of interchange of speech B, it is stored with the same elements, as well as mineral A, and in the first time, with concentrated hydrochloric acid, the gas is seen with the smell of "rotten yauts". With the interaction of gases one by one, a simple speech of the same color and water is established. Write a description of the reactions.

Decision

So when you go to the river B of hydrochloric acid, you see water H 2 S (gas і from the smell of "rotten yєts") (rivnyannya 3), then the offense is mineral є sulphides. In the process of vitriol production of hydrochloric acid and inoculation of vipal FeS 2 (1). SO 2 - gas with a pungent odor shows powerrenewal and reacting with bromine water give two acids: sirchan and hydrobromic (2). With the interaction of a sour gas (oxidizing) and sirkovnyu (protagonist), sirka is established - it is a simple talk of the same color (4).

1) 4FeS 2 + 11O 2 = 2Fe 2 O 3 + 8SO 2

2) SO 2 + Br 2 + 2H 2 O = H 2 SO 4 + 2HBr

3) FeS + 2HCl = FeCl 2 + H 2 S

4) SO 2 + 2H 2 S = 3S ↓ + 2H 2 O

4. Nitric acid was neutralized with kharcha soda, the solutions were boiled and the excess was fried. When the speech was approved, it was added to the acidification with the acidic acid of the potassium permanganate, which was unbarred at the same time. The nitrogen-mixed product of the reaction was placed in a solution of caustic soda and a zinc saw was added, at the same time the gas was seen with a strong characteristic odor. Write a description of the reactions.

Decision

Sodium nitrate is adopted to neutralize the conflict (1). Nitrate, set with metals, should stand in a row with more Mg, open up with the set of nitrites and acidity (2). Permanganate kaliyu KMnO 4 , Scho oily fermentation, є strong oxidizing in the acidic middle and oxidizing sodium to NaN nitrate+5 O 3 , Itself update to Mn+2 (Barless) (3). When zinc interacts with a wide meadow, an atomic water is seen, which is even a strong precursor, for that sodium nitrate NaN+5 O 3 update to amiaku N-3 H 3 (4).

1) HNO 3 + NaHCO 3 = NaNO 3 + H 2 O + CO 2

2) 2 NaNO 3 = 2NaNO 2 + O 2

3) 5NaNO 2 + 2KMnO 4 + 3H 2 SO 4 = 5NaNO 3 + K 2 SO 4 + 2MnSO 4 + 3H 2 O

4) NaNO 3 + 4Zn + 7NaOH + 6H 2 O = NH 3 + 4Na 2 Zn (OH) 4

5. Nevidomy metal was burned in acid. The product of the reaction, in conjunction with the carbon dioxide gas, will make two words: solid, like in conjunction with the solution of hydrochloric acid and the vision in carbon dioxide, І gas-like simple speech, which will adapt the fire. Write a description of the reactions.

Decision

Gas, which is used for burning - kissen (4). When metals are burned in acid, oxides and peroxides can be set. Oxide to give only one speech when interacting with a carbonic acid gas - sil carbonate, to that, coastal metal, sodium, which is a peroxide (1). During the interaction with the carbonic acid gas, the power is set and the kissen is seen (2). Carbonate with acid and carbon dioxide gas (3).

1) 2Na + O 2 = Na 2 O 2

2) 2Na 2 O 2 + 2CO 2 = 2Na 2 CO 3 + O 2

3) Na 2 CO 3 + 2HCl = 2NaCl + H 2 O + CO 2

4) O 2 + C = CO 2.

6. Hydroxide of trivalent chromium was treated with hydrochloric acid. Potash was added to the confusion, but when sieges were seen, they were added to the concentration of poisons, and as a result the sieges were broken. To add a surplus of hydrochloric acid to the green color. Write a description of the reactions.

Decision

Chromium hydroxide Cr (OH) 3 - amphoteric. With hydrochloric acid give CrCl 3 (1), since it is fixed with a weak base and a strong acid, that will allow hydrolysis on the cation. Potash - calcium carbonate K 2 CO 3 statements with a strong base and a weak acid, go for anion. Two salts are used to drive one by one, to the same hydrolysis until the end of the day: until coverage Cr (OH) 3 і CO 2 (2). Cr (OH) 3 in the surplus meadow yes hexahydroxochromite calium K 3 Cr (OH) 6 (3). When there is an excess of strong acid, two salts are set up (4).

1) Cr (OH) 3 + 3HCl = CrCl 3 + 3H 2 O

2) CrCl 3 + 3K 2 CO 3 + 3H 2 O = 2Cr (OH) 3 ↓ + 3CO 2 + 6KCl

3) Cr (OH) 3 + 3KOH conc. = K 3 Cr (OH) 6

4) K 3 Cr (OH) 6 + 6HCl = CrCl 3 + 3KCl + 6H 2 O.

7. The product of lithium interaction with water was drenched in water. As soon as the gas was seen, it was too sour, and when heated, it was passed over a platinum catalyst; gazova sumish mala buri kolіr settled. Write a description of the reactions.

Decision

When nitrogen and lithium are interconnected, nitrid lithium is established (1), which develops into water with visions of amiak (2). Amino acid is oxidized by acid in the presence of a platinum catalyst to nitrogen (II) oxide, but not to oil (3). Relief of brown gas NO 2 s NO is seen spontaneously (4).

1) 6Li + N 2 = 2Li 3 N

2) Li 3 N + 3H 2 O = 3LiOH + NH 3

3) 4NH 3 + 5O 2 = 4NO + 6H 2 O

4) 2NO + O 2 = 2NO 2.

8. Magnesium silica was treated with a solution of hydrochloric acid and the gas was burnt. The solid product of the reaction was mixed with soda ash, heated to melt, and vitrimized for an hour. After cooling, the product of the reaction (vikoristovuyutsya under the name "Ridke Sklo") was removed from water and treated with a solution of sirchanoic acid. Write a description of the reactions.

Decision

During the interaction of magnesium silica with hydrochloric acid, silane gas is set up (1). Win self-borrowing on power, fixing silicon oxide (solid speech) and water (2). When fused with silicon oxide in a meadow, or with soda, sodium silikate ("little sklo") (3). Sіrchan acid, yak is strong, vitisnya mild silicic acid in the range, yak is insoluble in water (4).

1) Mg 2 Si + 4HCl = 2MgCl 2 + SiH 4

2) 2SiH 4 + 2O 2 = SiO 2 + 2H 2 O

3) SiO 2 + Na 2 CO 3 = Na 2 SiO 3 + CO 2

4) Na 2 SiO 3 + H 2 SO 4 = Na 2 SO 4 + H 2 SiO 3 ↓.

9. When the orange color is heated, it will open up; The middle of the product is a gas-free gas and a solid green color. As soon as the gas is seen, it reacts from the lithium when the heating is low. The product of the last reaction is in the interaction with water, when you see the gas with a pungent odor, which can be emitted, for example, min, from the oxides. Write a description of the reactions.

Decision

Gas with a pungent odor, which could be thrown from the oxides (level 4) - amiak (level 3). A river of orange color, which can be folded into the vision of nitrogen (no gas) and the statements of a firm speech of green color Cr 2 O 3 - ammonium dichromate (NH 4) 2 Cr 2 O 7 (Rivnyannya 1), with the interaction of lithium with water, amiak is seen (3).

1) (NH 4) 2 Cr 2 O 7 = t N 2 + 4H 2 O + Cr 2 O 3

2) N 2 + 6Li = 2Li 3 N

3) Li 3 N + 3H 2 O = 3LiOH + NH 3

4) 2NH 3 + 3CuO = N 2 + 3Cu + 3H 2 O.

10. To an unseen river, a red-colored color was heated in chlorine and the product of the reaction was broken up in water. At the end of the day, they gave it to the meadow; When the product is heated to a roast, such as corn coli, with coke, the wine is rinsed into a red wine. Write a description of the reactions.

Decision

Metal red color - mid. When heated with chlorine, chloride mіdі-II СuСl is set 2 (1). When added to the range of the meadow, the siege of the blakite koloru Cu (OH) 2 - hydroxide midi-II (2). When heated, the wine is deposited on the oxide of midi-II black colora (3). When the oxide is heated with coke (C), honey is introduced.

1) Cu + Cl 2 = CuCl 2

2) CuCl 2 + 2NaOH = Cu (OH) 2 ↓ + 2NaCl

3) Cu (OH) 2 = CuO + H 2 O

4) CuO + C = Cu + CO.

11. Sil, trimmed with zinc oxide and sirchan acid, fried at 800 about C. The solid product of the reaction by concentrating it in the meadow and passing the carbon dioxide gas through the removal of the rods. Write down the descriptions of the reactions described.

Decision

When zinc oxide is interchangeable with sirchanic acid, sil zinc sulfate ZnSO 4 (1). At high temperatures, sulfates of metal oxides form a solution to metal oxide, pure gas and acid (2). Zinc oxide is amphoteric, which, in conjunction with the meadow, is made with sodium tetrahydroxotsinkate Na 2 Zn (OH) 4 (3). When carbon dioxide is passed into the water, a vugic acid, a complex, and a precipitate of zinc hydroxide are set (4).

1) ZnO + H 2 SO 4 = ZnSO 4 + H 2 O

2) 2ZnSO 4 = 2ZnO + SO 2 + O 2

3) ZnO + 2NaOH + H 2 O = Na 2 Zn (OH) 4

4) Na 2 Zn (OH) 4 + CO 2 = Na 2 CO 3 + Zn (OH) 2 ↓ + H 2 O.

12. Mercury-II nitrate was added to the middle shavings. The roschin was filtered and the filtrate was poured over the drips to the correct size, which is to take revenge on sodium hydroxide and ammonium hydroxide. At the same time, a siege was set up for a short time, as the razchinyavsya razchinyavsya razchinyavsya razchina yaskravo-blue colora. When the amount is added to the loss, the excess amount of sirchanoic acid is added to the color. Write a description of the reactions.

Decision

It’s worthwhile to stand next to a row of metals more than mercury, so there’s a reason for the difference in salt (1). When the medium-II nitrate is added to the meadow, the non-transient hydroxide midi-II Cu (OH) 2 (2), which is classified into a superfluous amiaku, creating a complex solution to the color-blue Cu (NH 3) 4 (OH) 2 (3). With the addition of sirchanoic acid, it will ruin, and the razchin of the infusion of blakite preparation (4).

1) Hg (NO 3) 2 + Cu = Ng + Cu (NO 3) 2

2) Cu (NO 3) 2 + 2KOH = Cu (OH) 2 ↓ + 2KNO 3

3) Cu (OH) 2 + 4NH 4 OH = Cu (NH 3) 4 (OH) 2 + 4H 2 O

4) Cu (NH 3) 4 (OH) 2 + 5H 2 SO 4 = CuSO 4 + 4NH 4 HSO 4 + 2H 2 O

Brazil is acidic, so there is a surplus of acid.

13. Chervonium phosphorus was burned in an atmosphere of chlorine and a drop of water was added to the product of the reaction. To see the speech, they put it into a surplus of water, they gave it a golden powder, and the gas-like product of the reaction was passed over a heat, oxidized to the oxide of a bivalent medium, by means of a plate. Write down the descriptions of the reactions described.

Decision

When phosphorus is mined, phosphorus chloride-V PCl is added to the excess chlorine 5 (1). With a small amount of hydrolysis of water, chlorine water appears and metaphosphoric acid is set up (2). Zalizo vitisnya water from acids (3). Water was mainly used for metal oxide (4).

1) 2P + 5Cl 2 = 2PCl 5

2) PCl 5 + 3H 2 O = HPO 3 + 5HCl

3) Fe + 2HCl = FeCl 2 + H 2

4) CuO + H 2 = t Cu + H 2 O.

14. Rechovina, removed during the heating of the golden scale in the atmosphere with water, was added to the hot concentrated syrchan acid and heated. Otrimanie razchin viparili, the surplus razchinit in the water and chipped razchin chloride barіyu. Rozchin was profiled and a middle plate was brought into the filtrate, and after a ten hour it was cleared. Write a description of the reactions.

Decision

When heated metal oxides, grain of gold scale Fe 3 O 4, with water metal renewal (1). Zalizo does not react with concentrated sirchanic acid with normal drainage, but it does not react with heating (2). Sulfate of zaliza-III with a chloride bar makes precipitation of sulphate barium (30. Chloride of zaliza-III shows the power of oxidation and development of medium (4).

1) Fe 3 O 4 + 8H 2 = 3Fe + 4H 2 O

2) 2Fe + 6H 2 SO 4conc. (Hor.) = Fe 2 (SO 4) 3 + 3SO 2 + 6H 2 O

3) Fe 2 (SO 4) 3 + 3BaCl 2 = 3BaSO 4 ↓ + 2FeCl 3

4) 2FeCl 3 + Cu = 2FeCl 2 + CuCl 2.

15. Negashene was fried with too much coke. The product of the reaction, after being treated with water, is vicorized for clinging of pure and carbon dioxide gases. Write a description of the reactions.

Decision

Frying quicklime with coke is an industrial way of removing calcium carbide (1). During hydrolysis of calcium carbide, acetylene appears and calcium hydroxide is formed (2), which can be reacted with acidic oxides (3, 4).

1) CaO + 3C = CaC 2 + CO

2) CaC 2 + 2H 2 O = Ca (OH) 2 ↓ + C 2 H 2

3) Ca (OH) 2 + SO 2 = CaSO 3 ↓ + H 2 O

4) Ca (OH) 2 + CO 2 = CaCO 3 ↓ + H 2 O.

16. Above the surface of the liquid soda poured into the flask, electric discharges were passed through, when they were drunk in the flask, they were blown into a storm of colir, which appeared in a decade. They carefully viparized and set them up, but a solid surplus is a sum of two salts. When there is a heat up of the summit, there is gas and there is a single speech. Write a description of the reactions.

Decision

During electric discharges, nitrogen enters into a reaction with acidic gas, nitrogen oxide (1), which is easily oxidized by acidic powder to nitrogen oxide-IV brown color (2). Nitrogen-IV oxide, which can be found in meadows, fixes two salts - nitrate and nitrite, which is also an anhydride of two acids (3). When heating nitrate, it is laid out in the formulation of nitrite and visions of acidity (4).

1) N 2 + O 2 = 2NO

2) 2NO + O2 = 2NO 2

3) 2NO 2 + 2NaOH = NaNO 3 + NaNO 2 + H 2 O

4) 2NaNO 3 = 2NaNO 2 + O 2.

17. Hydrochloric acid was carefully added to the pyrolusite. They allowed the gas to flow into a cold glass, half filled with cold liquor. When the reaction was over, the glass was covered with cardboard and covered with light; a dozen hour later, they brought in a smoldering splinter, yaka slept away. Write a description of the reactions.

Decision

Interaction of hydrochloric acid with pyrolusite MnO 2 - laboratory method for eliminating chlorine (1). Chlorine in cold form, calcium hydroxide and two salts, calcium chloride and hypochlorite (2). Hypochlorite is a nonsense of speech and, when illuminated, it is laid down with visions of a song (3), the decision of which to bring it to the side has fallen asleep (4).

1) MnO 2 + 4HCl = Cl 2 + MnCl 2 + 2H 2 O

2) Cl 2 + 2KOH = KCl + KClO + H 2 O

3) 2KClO = 2KCl + O 2

4) C + O 2 = CO 2.

Seeing gas. Head of ADI s chemistry with solutions: Interconnection of different classes of inorganic speeches Umov set up a siege. twir of reliability

In a test tube with a solution of salt X, a solution was given to the speech Y. The result was a reaction, I can describe the coming sooner rather than later S 2 + 2H + = H 2 S.

1) sodium sulfide;

2) vugic acid;

3) chlorine day;

4) sulfide zaliza (II);

5) calium sulfite;

At the test tube with the solution of the salt X, they gave the answer to the U.

1) calcium nitrate;

2) chloride bar;

H) hydrochloric acid;

4) calcium carbonate;

5) sirchan acid;

Write down in the table the numbers of the addresses given in all letters.

In a test tube with a range of sodium salt X, they gave the answer to U.

S 2+ Fe 2+ = FeS.

From the proponents of the change of speech X and Y, which can enter into the described reaction.

1) sodium sulfide;

2) sodium sulfite;

3) sirvodden;

4) hydroxide zaliz (II);

5) sulfate of zaliz (II);

Write down in the table the numbers of the addresses given in all letters.

In a test tube with a salt solution, X was given a U. From the proponents of the change of speech X and Y, which can enter into the described reaction.

1) calcium sulfite;

2) sodium hydroxide;

H) sulfate of zaliz (II);

4) chlorine day;

5) sodium nitrate.

Write down in the table the numbers of the addresses given in all letters.

At the test tube with the range of the speech, X was given the acidity and U.

From the proponents of the change of speech X and Y, which can enter into the described reaction.

1) sodium sulfide;

2) vugic acid;

3) sirchan acid;

4) hydroxide barium;

5) calcium hydroxide.

Write down in the table the numbers of the addresses given in all letters.

At the test tube with the solution of the speech, X was given the solution of the salt U. From the proponents of the change of speech X and Y, which can enter into the described reaction.

1) sulfate of zaliz (II);

2) hydrochloric acid;

3) sodium hydroxide;

4) calcium nitrate;

5) sulphate mіdі (II).

Write down in the table the numbers of the addresses given in all letters.

At the test tube with a firm, unreliable at the water with a speech, X was given a breakdown of the speech of U. From the proponents of the change of speech X and Y, which can enter into the described reaction.

1) calcium carbonate;

2) sodium hydroxide;

H) sulfate barіyu;

4) sirchan acid;

5) oxide midi (II).

Write down in the table the numbers of the addresses given in all letters.

At the test tube with the range of the speech, X was given the solution of the salt Y. The result was a reaction, I would describe it as soon as possible: CO 3 2- + 2H + = H 2 O + CO 2.

From the proponents of the change of speech, X and Y. can enter into the described reaction.

1) calcium hydrocarbonate;

2) calcium hydroxide;

3) restic acid;

4) sirchan acid;

5) sodium carbonate.

Write down in the table the numbers of the addresses given in all letters.

At the test tube with the solution of the speech, X was given the solution of the salt U. From the proponents of the change of speech X and Y, which can enter into the described reaction.

1) chloride mіdі (II);

2) hydrochloric acid;

3) sodium hydroxide;

4) sodium nitrate;

5) zaliza sulfate (III).

Write down in the table the numbers of the addresses given in all letters.

In a test tube with a range of acid, X gave a solution to the problem of U.

From the proponents of the change of speech X and Y, which can enter into the described reaction.

1) potassium sulfate;

2) hydrohydric acid;

3) sirchan acid;

4) ammonium sulfide;

5) sodium sulfite.

Write down in the table the numbers of the addresses given in all letters.

1) Na 2 ZnO 2;

2) Zn (OH) 2;

3) ZnO;

4) Na 2;

5) NaOH.