A deyakiy element of 7 young, strong oxides. "Caveats" of food, for chi will have two - chotiri. "Employment_2_determination of speech formulas"
1. Roles and evaluations
1. Are there molecules of gasoline in a 10-liter canister?
2. How to take revenge on more molecules - the organism of the reader, or if you are in a classroom?
3. In the process of dyhannya lyudin lives on kissen і vidikhaє in carbon dioxide gas. Zm_st cich gas in the inhaled and vidyhuvan in the table.
| O 2 | CO 2 |
|
| inhaling | ||
| see |
Osyag vidihu-vidihu - 0.5 l, the frequency of normal consumption is 15 vidikhiv per chilin.
1. Skіlki lіtrev kisnyu Lyudin lives for a year and skіlki vidіlya in carbon dioxide?
2. A class with a volume of 100 m 3 has 20 units. The windows and doors are closed. What will be the exchange of CO 2 during the lesson? (Absolutely no baking process - up to 0.1%).
4. Gas X is excellently dispensed with water. In one liter of water, 250 liters of gas X (n.o.) were reduced and the differences were removed, in which the mass part of X was 15.9%. Set formula X.
5. Nevidomy bivalent metal fixes three different salts with orthophosphoric acid. The share of the largest share of metal in the majority is 38.7%. Install metal and formulas of all salts.
6. The first person to smite into the handful of water. Vrantsi sipped a cup of tea, and 5 molecules were added to it from the same handful. Assess the supply of water on the Earth.
7. We beat one vidh-vidih. Molecules, like boules of your body, were poured into the atmosphere. In an hour, the cholovik in the inshy part of the Earth shattered the breath. After inhaling the molecules, how did they go to your body?
8. One of the characteristics of radioactive elements є the period in the fall is an hour, after the element it drops by half. The period for the period from the west to the cesium-137 becomes 30 rocky. In an hour it will fall apart: a) a quarter, b) three quarters, c) 99.9% of the total amount of cesium?
"Employment_2_determination of speech formulas"
2. The value of speech formulas
(Lomonosov, class 9, 2016) Before the warehouse of lead billets, there is an inorganic silt with lead, which can also be avenged in coal, water and kissen. Zm_st of the navazhchy element in the ts_y salt road is 20%, and the lightest - 13.3%. About all kinds of things - about mass or atomic ones? Establish the formula for the salt, as parts of the two elements are changed 4 times.
(School stage, 9th class, Moscow, 2015) A deyaky element set up 7 vivid, strong oxides, and all the stench may have an acidic character. In the lower part of the oxide mass, the acidity is 18.4%. First, start an unattractive element and expand the mass part of the sour into the whole oxide. Write down the typical reactions of food and lower oxide with water.
Allocation of molar mass to oxide and chloride of element s with a step oxidized to become 6: 17. What element will make spoluca?
Revenge to take revenge on sodium, phosphorus and kisin. Masova part of the price range is 47.06%. Just start the simplest speech formula.
In the sum of the oxide of the bivalent metal and carbonate, the mass fraction in the coal is 2.89%, and the mass fraction of the acid is 14.12%. Visnite metal.
(Lomonosov, class 9, 2016) Element X I will approve three gas-like compounds with fluorine. The best of them - A- 2 times more important in carbon dioxide, two of them - Bі C- Revenge the same number of atoms. gazi Aі C react with water, soluble in two acids. C with strong heat, it transforms into A... gas A when heated with a non-dispersed nickel, it gives me a fly, which is 4.67 times more important A. install element X, Gas Formulas A – C and write an explanation of all the reactions about how many people are in the factory.
Organizational speech is stored in all of two elements with equal mass parts. When boiling 14.4 g of the whole mixture in a vacuum vessel with a volume of 2.00 l at a temperature of 250 ° C, a vise of 108.7 kPa is removed. Establish the molecular formula of the speech.
When roasting in water 100 g of unhomed crystalline hydrate, 500 ml of the solution was removed with a molar concentration of 0.621 M. Establish the formula for the crystallohydrate.
(MZOSH, class 10, 2016) Zrazok metal weighing 3.47 g was recovered in a 20% meadow, with a total of 5.6 liters of gas (n.u.). The same kind of metal (the same mass) was burned on the ground, the products of the burning were increased in a 20% meadow, and 1.12 liters of gas (n.u.) were consumed with a whole lot. Visualize metal and explain the results of the experiments.
To the point of revealing 1.35 g of metal chloride (oxidation steps +2), a solution was given, about 0.51 g of hydrochloric acid salt, with 0.96 g of the precipitate. Induce the formulas of natural salts, as the stench reacted on top of it.
When the white crystalline speech is heated to 100 ° C, a gas appears and gas appears, in which mass fraction it becomes 72.73%. When there is a phosphoric anhydride at room temperature Binarna spoluka, in which mass part the sourness becomes 47.06%. Begin with a strong speech and product. Write a line against reactions.
Revision of the document
"Employment_3_1_Gasovie_laws"
3.1. gas laws
For the renewal of 10 liters of unattractive gas to a simple speech, 10 liters of water was needed, and when 10 liters of gas were placed in the open space, 15 liters of gas were approved (osyagi of gases for the same minds). Set the formula to the gas.
Through the sum_sh of two gases we passed an іskra. After the end of the reaction, the sum of the sum changed by one half (at constant temperature and vice). Propagate the warehouse of the wicked sum (in vol.%).
Amiak was heated up to 900 ° C, and then it got the idea of gas, and it was brought to the first minds. The strength of the sum was 1.4 times less than the strength of the American. Start a step to the store for Amiak.
The sum of the most important water is more important than water by 10%. How many H 2 molecules are added to one D 2 molecule in such a sum?
Sum of ethylene, acetylene and water, with a power of 0.478 g / l, if the flow over a platinum catalyst increases the power of up to 1.062 g / l (the power of gases is reduced to normal minds). Visit a warehouse for a great amount of gases at the office for a large amount of money.
The sum of two alkanes in the large-scale sport a : b power 1.00 g / l at a vice of 102 kPa and a temperature of 95 ° C. b : a 2.4 times more important. Establish alkane formulas and know aі b .
Revision of the document
"Busy_3_2_Mixes"
3.2. Zavdannya on sumіshі
(Moscow State University, 2015) The sum of ozic and propionic acids was neutralized with 86.15 ml of a 20% solution of calcium hydroxide with a strength of 1.3 g / ml. Having agreed on the differences, they viparized and fried it in an overly firm meadow, at the same time gas was seen with a thick one, by the way, until it was 0.914. Look for a gas warehouse and large areas with a new one. Protect the mass of acid particles in the wild.
The sum of nitrogen monoxide and nitrogen dioxide in a natural weight of 53 g is 9.03 × 10 23 atoms in nitrogen. Look for the number of cutaneous gas. How can the density of gases change when CO 2 is added to it (at constant temperatures and vice)?
The sum of magnesium and phosphorus was fried without access to food, then the product was divided into three parts. The first part was doused with water, the friend - too much hydrochloric acid, in both drops it was seen in 0.978 liters of gas (25 ° C, vice 1 atm). The third part of the product was heated with overly concentrated nitric acid, and for a full clay it was seen with nitrogen (IV) oxide, 136.3 ml of 15% KOH solution (strength 1.15 g / ml) was required. Reinstall a molar part of magnesium in the wicked summit.
When the sums are ignored, two organic spoluk only carbon dioxide gas and water are set. The bulk of the products is 32 g, and the bulk of the products is 5%. Establish a good and small warehouse of all kinds of goods, if it seems that the mass part in coal will become 40%.
(MZOSH, 2012) One liter of gas-like amount of two non-saturated carbohydrates with repeated hydrogenation can bring 1.8 liters of water. When one liter of fiery madness is burned, 2.2 liters of carbon dioxide are set. Please, start a clean and small warehouse of the sum. All obsyagi vimiryani with the same minds. Protect the wickedness of the wickedness in the water.
(VSOSh 2015 rock, final stage ) Natural gas, which is stored from some lower alkanes, weight 0.940 g / l at normal atmospheric viceі temperature і 25 ° С
Yakі z perakhovanih lower values can be significant for the whole gas unambiguously? Crack the value.
a) Average molar mass;
b) brilliance with normal minds;
c) the strength of the condensed gas;
d) molar parts of alkanes;
e) mass part of the coal in the sum;
f) obsyag kisnyu, necessary for the repeated burning of 1 liter of sum;
g) heat of light of 1 mol of sum in graph and water;
h) heat of combustion of 1 mole of sum.
Explain briefly why it is impossible to know the size.
Instead of methane in a given natural gas(In mole%).
dovidkovі danі You can do it.
heat of vaporization graphite: Q isp = -705 kJ / mol,
middle energy links: E(H-H) = 436 kJ / mol, E(C -C) = 334 kJ / mol, E(C-H) = 412 kJ / mol, heat of light: Q arr (CO 2) = 394 kJ / mol, Q sample (H 2 O) = 242 kJ / mol.
Rishennya (V.V.
The idea of \ u200b \ u200bindividual alkane in the fact that whether it is a sum of gas-like alkanes, right from a particular warehouse, you can see how an individual alkane with an average formula C x H 2 x +2 (x- the average number of atoms in carbon in molecules, rozrahovanie with urahuvannya molar parts of gases; there may be no criminals). For example, the sum of pryvnyh obsyagiv CH 4 and C 2 H 6 is characterized by the average formula C 1.5 H 5.
For such an "average" alkane, it is possible to develop all values, crim (c) and (g). It is possible for the first person to be aware of the fact that they do not know the strength of the native alkanes, and for the friend - the one who, for the purpose of determining the exact warehouse of the sum of 4 words, is not given.
1.a) g / mol.
For molar mass we know the average formula sum C x H 2 x+2, the price is required for the advanced projects
14x + 2 = 23, x= 1.5. The average formula of the sum is C 1.5 H 5.
b) With normal minds, all the lower alkanes are still gas, so
g / l.
e) The mass fraction in the coal can be known by the middle formula:
= 78.3%.
The same meaning can be made in a standard way, not in a vicious way. middle formula... Just 1 mole of sum, do not let me win a mol CH 4, b mol C 2 H 6, c mol C 3 H 8 і (1 a –b –c) Mole C 4 H 10. We can write down the average molar mass of sum:
23 = 16 a + 30 b + 44 c + 58(1– a – b – c ),
3a + 2b + c = 2.5.
Masova chateau vugletsyu in sumіshі:
Similar rosary can be shown for the values in points (f) - (h), so that you can know the specific values for the skin alkane okremo. So far we will be confronted only with the understanding of the middle formula.
f) Rivnyannya povnyanyya alkanov:
C x H 2 x +2 + (3 x+1) / 2 O 2 = x CO 2 + ( x+1) H 2 O
V(O 2) = (3 x +1)/2 V(C x H 2 x +2 ),
V(C x H 2 x+2) = 1 l, x = 1.5,
V(O 2) = 2.75 l.
g) We know the warmth of illumination of an individual alkane, x atoms in coal, from simple speeches:
x C (gr) + ( x+1) H 2 = C x H 2 x +2 + Q arr
For rejection of 1 blessed alkan treba viparuvati x moles graphite, rosirvati ( x+1) moles of H-H links, and then confirm ( x-1) moles of links C -C i (2 x+2) moles of C-H bonds. Surely due to Hess's law,
Q arr (C x H 2 x +2) = (–705) x – (x +1) 436 + (x –1) 334 + (2x +2) 412 = 17x+ 54 (kJ / mol)
at x = 1.5
Q sample (sum) = 171.5 + 54 = 79.5 kJ / mol.
h) For the equal reaction zgoryannya z p. (f),
Q combustion (C x H 2 x +2) = xQ arr (CO 2) + ( x+1) Q arr (H 2 O) - Q arr (C x H 2 x +2) =
= 394x + 242 (x+1) – (17x+54) = 619x+ 188 (kJ / mol)
at x = 1.5
Q combustion (sumіshі) = 6191.5 + 188 = 1116.5 kJ / mol.
2. The maximum possible amount of methane in the sum will be in times, if the part of the sum will be represented only by the natural gas - butane, and ethane and propane will be even malium. Apparently there is a fraction of methane in such a sum x max і visibly through its average molar mass:
16x max + 58 (1 x max) = 23,
x max = 0.833 = 83.3%
The minimum amount of methane in the amount of methane seems to fall, if the only part of it is crazy to dispose of only the lightest gas - ethane.
16x min + 30 (1 x min) = 23,
x min = 0.5 = 50%
Відповіді.
1.a) M Wed = 23 g / mol.
b) = 1.03 g / l.
c) Definitely not possible.
d) Definitely not possible.
e) (C) = 78.3%.
e) V(O 2) = 2.75 l.
g) Q sample (sum) = 79.5 kJ / mol.
h) Q combustion (sum) = 1116.5 kJ / mol.
Deyaki elements may be 7 different strong oxides and all the smell is acidic. in the lower part of the oxidation of the mass fraction of the price of 18.4%, of write an explanation of the reaction of food and lower oxide Thanks in advance
indications:
In the lower oxide, the valence of the element is minimal, tobto = 1, which means that the formula for oxide E2O M (O) in oxide = 16 / 0.184 = 87. Ar (E) = (87-16) / 2 = 35.5; E = chlorine. Viscous oxide Cl2O7 ω (O) = 16 * 7/183 * 100 = 61.202% Cl2O7 + H2O = 2HClO4 Cl2O + H2O = 2HClO
Similar food
- Vona was spinning with her feet, lightening the wonder in the eyes of Tekhon and asking for a handout. From the cap piled on the eyes of the cap, distrustful eyes flashed alertly. know the word
- Yak change gree children and children in the role of fso wіkom what is new seven ?? chi 10 rock_v
- In the yard, hens and lambs. Lambs are 3 times smaller than chickens. Number of nig chickens and lambs one 40. Slices of chickens and slices of lambs by the yard?
- The fox The wolf the bear smart The fox is smarter than the wolf smart silly brave kind helpful bad dangerous
- Naivazhlivіsha zalіza masoyu 0.5-0.65 grams
- All the Komi ?? are numbered at the points below the sentences from the text read. Vipishit numbers, scho mean who mіzh parts folding proposition, Tied with a mediocre band. George opened the valve of the rotary system, (1) pulling the vibrator to the launch, (2) moving it, (3) hitting it twice, (4) hitting it with a sinister, (5) sounding a loud sound. The shovels of gwent were angry at the (6) blinking disk. Guchna tremtinnya walked along the steel body of the car. The mechanic and the minder thumped the pads with the pads, (7) and lit, (8) roared the engine, (9) strained the caponier, (10) gently plodded along the Rozdolny steppe expanse. (E. Podolny)
Size: px
Fix the show from the side:
transcript
1 VSSEROSІYSKA OLIMPIADA SHKOLYARIV Z ХІМІЇ uch. m SCHOOL STAFF 9 class Decisions and evaluation criteria In the assessment of six employees, it’s worth taking a decision, for which participant typing the most bali, so that I won’t be able to win the best ball. The maximum number of balls is a Cheerful part. In which particle are 11 protons, 10 electrons and 7 neutrons? First of all, the warehouse, the charge, the usual molecular weight. Write the formulas of two z'єdnan, before the warehouse of which to enter a part. Proton is 1 more, lower elektroniv. Otzhe, the part has a charge of +1. Neutrons are less, less protons, even, before the storage of the part, atoms enter into the water, in some neutrons there is no amount of atoms = 4, the minimum number of atoms H. 7 protons and 7 neutrons are lost in nitrogen-14: 14 NH. + 4 іon ammonia 4 bali Charge: = +1 2 bali Allowable molecular weight: = 18 or = 18 2 bali Formulas: NH 4 Cl, (NH 4) 2 CO 3 or інші salts of ammonia 2 bali 2. The highest number of oxides. A deyaky element of 7 young, strong oxides, and all the stench may have an acidic character. In the lower part of the oxide mass, the acidity is 18.4%. Start an unattractive element and expand the mass part of the sourness in the whole oxide. Write down the typical reactions of food and lower oxide with water. Supposedly, the formula of the lower oxide is R 2 O. The molar mass of the oxide is: M (R 2 O) = 16 / 0.184 = 87 g / mol, M (R) = (87 16) / 2 = 35.5 g / mol ze chlorine, the formula for the oxide Cl 2 O 5 balіv Viscous oxide Cl 2 O 7. ω (o) = 7 16 / (, 5) = 0.612 = 61.2% 3 bali Obidva acid oxide, when reacting with water, acids are established: Cl 2 O + H 2 O = 2HClO Cl 2 O 7 + H 2 O = 2HClO 4 1
2 3. Equivalent reactions Lower indications of experimental chemical reactions, in which the formulas of the actions and performance are omitted. Save all omissions. 1) Cu 2 O + H 2 = Cu + 2) 2H 2 S + 3 = H 2 O + 2SO 2 3) 6 + O 2 = Fe 3 O 4 4) 2AgNO 3 = Ag + 2NO 2 + 5) 2KOH + = K 2 SO 4 + H 2 O 1) Cu 2 O + H 2 = 2Cu + H 2 O 2) 2H 2 S + 3O 2 = 2H 2 O + 2SO 2 3) 6FeO + O 2 = 2Fe 3 O 4 4 ) 2AgNO 3 = 2Ag + 2NO 2 + O 2 5) 2KOH + H 2 SO 4 = K 2 SO 4 + 2H 2 O Passes are easy to use a logical way, in accordance with the law of protection of the masi, they can be found in a way that is unavailable to scholars. Application of reaction 3. In some part, it is impossible to get a connection with a factor of 6, so the number of Fe atoms is minimal. In the left part, 2 atoms of O enter up to the O 2 store, and 6 into the unseen speech. Zvidsy will be recognized in the livia part of 6FeO. 3. Long-standing atmosphere. In the distant past, millions of years ago, the surface of the Earth was even hotter, and in the atmosphere there was no sourness and nitrogen, it was stored in carbon dioxide, methane (CH 4) and water steam. Tsikavo, with a wide range of atmosphere, the bool is approximately the same as in the normal hour. Vazhayayu, how old atmosphere was formed only with methane and carbon dioxide, but more often, with any quantity of these gases (in terms of the number of molecules), the strength of the old-fashioned tradition will be more expensive. The average molar mass of the minor power is equal to 29 g / mol. The average molar mass of the old food is 29 g / mol. Nekhai φ will mean a part of the gas. 16φ (CH 4) + 44φ (CO 2) = 29 φ (ch 4) + φ (co 2) = 1 φ (ch 4) = 15/28 = 0.54 = 54% 6 bal. expensive molar particles (inheritance from Avogadro's law), to that the ratio of large portions to the relative number of molecules: 2
3 N (CH 4) / N (CO 2) = φ (ch 4) / φ (co 2) = 15/13 The same result can be corrected from the “Vajel rule”: N (CH 4) / N (CO 2) = (M (CO 2) M avg) / (M av M (CH 4)) = = (44 29) / (29 16) = 15 / bal 4. Pairwise interaction. Given such words: sulphate midi (ii), chloride barium, oxide of zaliz (iii), oxide of carbon (iv), oxide of sodium, medium, zalizo, sodium carbonate, water. How many of these rivers will enter into a reaction one by one without a second, or at a water break at room temperature? To guide the family of five young reactions. For skin reactions, it should be considered to which type of won. You can react: Na 2 O + H 2 O = 2NaOH Na 2 O + CO 2 = Na 2 CO 3 BaCl 2 + CuSO 4 = BaSO 4 + CuCl 2 2CuSO 4 + 2Na 2 CO 3 + H 2 O = Cu 2 (OH ) 2 CO 3 + CO 2 + 2Na 2 SO 4 Fe + CuSO 4 = Cu + FeSO 4 substituted with Na 2 CO 3 + CO 2 + H 2 O = 2NaHCO 3 Na 2 O + H 2 O + CuSO 4 = Cu (OH ) 2 + Na 2 SO 4 і 2NaOH + CO 2 = Na 2 CO 3 + H 2 O BaCl 2 + Na 2 CO 3 = BaCO 3 + 2NaCl for skin from five rivnyans 2 bali each (for speech, 0.5 points for performance, 0.5 points for the type of reaction). 6. High-school synthesis. A water suspension of 1 manganese oxide (iv) (2) was placed near the Würz flask (the small one is designated by the number 1) and was sealed with a cork, a drip funnel was inserted into the yaku Bula (3). At the droplet funnel there was a breakdown of the speech X. We turned on the tap (4) and added the breakdown of the call of X at the Würz flask, at once the drunkard reacted. The black half of the burning fire has become bright, the fire has become more intense. 1 Suspension of a suspension of particles of solid speech in ridin. 3
4 When the reaction is finished, the jar (5) was filled with a barless gas Z, which has a very small smell. At a can of gas Z, they poured the difference between the words X, chickened out and took away the sirchan acid. A. Viznachte, as speeches are encrypted by letters X, Y and Z. B. Write a line of offensive reactions: denying gas Y from speech X; mining of fire in Y with gas Z approval; to develop the hydrochloric acid in the course of interaction X with Z. Q. What reactions should be carried out, to bring, how can the result of all the transformation result in the hydrochloric acid? G. Would I mark the differences of speech X vicorists in the home pharmacy? E. Propagate one more way of removing the acid, which can be used in the school laboratory. A. Rechovina X water peroxide H 2 O 2, Y acid O 2, Z pure gas SO 2. By the skin of the skin MnO2 B. 2H 2 O 2 2H 2 O + O 2 S + O 2 = SO 2 H 2 O 2 + SO 2 = H 2 SO 4 According to the dermal reaction of V. Yaksho to the cut-off size to give a litmus, then the indicator of the receipt of the red. Tsey the fact to bring, that the acid was established. As soon as the confusion is resolved to the chloride of the barium, then the siege of the white colora will take place. The reaction is to bring the presence of sulfate ions into the discarded speech. BaCl 2 + H 2 SO 4 = BaSO 4 + 2HCl 4
5 g. 3% solution of peroxide water stagnates in the quality of disinfecting and cleaning roof mats for washing and rinsing, for cleaning skin curves, wounds and wounds. D. You can be pro-proponated with different options, for example, passing water through the solution to sulphate midi (ii): CuSO 4 + H 2 S = H 2 SO 4 + CuS For good reason 5
1 VSSEROSIYSKA OLIMPIADA SHKOLYARIV Z XIMIS 2014 2015 r MUNICIPAL'NY ETAP. 9 CLAS Rishennya and evaluation criteria olympiadnykh zavdan Pidsumkov has an assessment of six proponents to get five
VSSEROSIISKA OLIMPIADA SHKOLYARIV Z ХІМІЇ. 2016 2017 account m MUNICIPAL ETAP. 9 KLAS Zavdannya, revisions, evaluation criteria Zagalnye recommendation: as in the established consumer goods, the stench is bound to be
Хімія 8 class. demonstration option 2 (90 quilins) 1 Diagnostic themed robot 2 from preparation to the OGE on ХІМІЇ for the topics “Basic classes of inorganic spoluk. Genetic link between classes
District Misto (settlements) School Klas Pryzvische Im'ya By Batkov Diagnostic Robot 1 on ХІМІЇ 21 leaf fall 2011 Rock 9 class Option 1 Хімія. Class 9 Option 1 2 Instructions on robotics
VSSEROSIISKA OLIMPIADA SHKOLYARIV Z ХІМІЇ. 014 015 RIK SHKILNY ETAP. 10 CLASS 1 Criteria for the assessment of olympiadic establishments
Chemia. Class 9 Demonstration Option 1 Project of Robot Examination for the State Pedagogical Attestation of the IX Classes for the State Educational Establishment 2010 new form)
Хімія 9 class. Demonstration option 6 (90 quilins) 1 Diagnostic thematic robot 6 from preparation to the OGE on ХІМІЇ on the topic “Metals. Genetic linkage between main classes inorganic speeches»
The topic is electrolytic discourse. REACTION OF THE ONE COMMUNICATION Reversing the element for the recipient Form of the plant Max. point 1. Electrolytes and non-electrolytes VO 1 2. Electrolytic dissociation VO 1 3. Mind non-vortex
Budov of the atom and the periodic law of D.I. Mendeleva 1. The charge of the nucleus of an atom of a chemical element, roztasvanny in the 3rd period, IIA group road 1) +12 2) +2 3) +10 4) +8 2. For what reason is the charge of the atomic nucleus (+ Z),
The project of the Robot Exam for the State Pedagogical Assessment of the 9th Classes of the Grade 9th Grade Educational Institutions (in a new form) according to the XIMI Robot Exam for
VSSEROSIISKA OLIMPIADA SHKOLYARIV Z ХІМІЇ. 2017 2018 academic year m MUNICIPAL ETAP. 9 KLAS Zavdannya, revisions, evaluation criteria Zagalnye recommendation: as in the established consumer goods, the stench is bound to be
Хімія 9 class. Demonstration option 6 (45 chilins) 1 Diagnostic thematic robot 6 from preparation to the OGE on ХІМІЇ on the topic “Metals. Genetic link between the main classes of inorganic speech "
Project Derzhavna (pidsumkov) attestation 2010 (in new form) on ХІМІЇ start, mastered the main outbound programs Demonstration version of control materials
1. Why is the charge of the nucleus of an atom in carbon? 1) 0 2) +6 3) +12 4) -1 2. What is the spil in atoms 12 6C and 11 6C? 1) Mass number 2) Number of protons 3) Number of neutrons 4) radioactive power Check in
Part 1 Show to the building 1 15 є one digit, as it is shown to the correct number. Write down a full number in the text field in the text of the robot. 1 Number of occupied electronic balloons on the door 1) number
Chemia. Class 9 Option ХІ90103 Відповіді to the factory Default Відповід 16 23 17 24 18 112 19 214 Хімія. Class 9 Option ХІ90104 Відповіді to the factory Відповід 16 25 17 15 18 341 19 323 Хімія. Class 9 option
demonstration option Examining robots to carry out in 2010 the state (pidsumkovoi) attestation (in the new form) on ХІМІЇ start, mastered the basic educational programs of the main
Хімія 9 class. Demonstration version 4 (90 hvili) 1 Diagnostic thematic robot 4 on preparation to OGE on ХІМІЇ for the topics “Electrolytic dissociation. Reactions of ion exchange. hydrochloric acid recovery
Full-time stage. Class 9 Decision. Management 1. Molecules of two folding binarials A and B to replace the same number of electrons, the charge of which in molecules is -28.8 * 10-19 Cl. Tsі speeches vikoristovuyutsya
State (pidsumkova) attestation of vypuskniks of the 9th class in the outlaw setting of 2009 (in the new form) according to the ХІМІЇ Demonstration version of the substitution procedure for the preparation of the Federal State
Хімія 9 class. Demonstration version (45 quills) 1 Demo version of robotics 2 by CHEMISTRY Instructions on the screening of robots On the screening of robots by chemistry, 45 quills are introduced. The robot is stored in two parts
1. The main power of the manifestation of the oxide of the element: 1) serum 2) nitrogen 3) barium 4) carbon 2. Yak from the formulas leads to the virality of the degree of dissociation of electrolytes: 1) α = n \ n 2) V n = V \ n 3) V n = V \ n 3) =
Option 3 Part 1. When you visit the building 1 15, insert only one digit, as the number will be correct. 1 On the hovering little one 1 images the model of the atom 1) silicon 2) sirki 3) cherry
All-Russian Olympiad School students Municipal stage Management of chemistry 9th grade THEORETICAL TOUR Zavdannya 9- (6 points) How many electrons and protons to enter to the warehouse of the property NO? Render. Point
VSSEROSІYSKA OLIMPIADA SHKOLYARIV Z ХІМІЇ MUNICIPALNY ETAP 2014 Methodical recommendations for decisions and assessments of olympiadic establishments 9th grade Startup 1. 10 points at once 1 2 3 4 5 6 7 8 9 10 1 3 2 1
Robot rehearsal for training to the OGE on XIMIS 13 February 2015 Rock 9 class Option XI90301 Viconano: PIB class
Part 1 Show to the building 1 15 є one digit, as it is shown to the correct number. Write down a full number in the text field in the text of the robot. 1 The number of electrons in the largest electronic sphere of the atom,
1. Yaka reaction to a short Ionny Rivnyannya H + + OH - = H 2 O? 1) ZnCl 2 + 2NaOH = Zn (OH) 2 + 2NaCl, 2) H 2 SO 4 + CuSO 4 = CuSO 4 + 2H 2 O, 3) NaOH + HNO 3 = NaNO 3 + H 2 O 4) H 2 SO 4
Option 1. 1. The skin is carried to acids from two branches 1) Н 2 S, Na 2 CO 3 2) K 2 SO 4, Na 2 SO 4 3) H 3 PO 4, HNO 3 4) KOH, HCl 2. hydroxide mіdі (ii) type of formula 1) Cu 2 O 2) Cu (OH) 2 3) CuOH
Demonstration version of control virtual materials for carrying out in 2011 the state (new form) attestation (in the new form) according to ХІМІЇ.
VSSEROSISKA OLIMPIADA SHKOLYARIV W X XIMIS 2015 2016 academic year m SCHKILNY STAP 10 class Decisions and evaluation criteria
Robot trainer according to ХІМІЇ 9 class 17 of the fierce 2017 rock Option ХІ90303 Viconano: ПІБ class Instructions according to the robotics presentation Dana diagnostics of the robot is presented on the first test model
Trenuvalny version of examination robots for training to the OGE for students of 8 classes. Instructions for the execution of the robot The examination of the robot is stored in two parts, which includes 22 parts. part
ZAVDANNYA 3 Apply the solution of tasks Application 1. In those test tubes without writing, there are differences between such words: sodium sulfate, sodium carbonate, sodium nitrate and sodium iodide. Show me for help
Explains the note before diagnostics and trenuvalny robots in DPA (ЄDI) format: Dana robot stored in DPA (SDI) format up to demo version, Published on the FIPI website
Class 9 Mind. Management 1. Molecules of two folding binarials A and B to replace the same number of electrons, the charge of which in molecules is -28.8 * 10-19 Cl. Tsi speech vikoristovytsya yak components
Input control class 9 (natural science) Option 1 1. Scheme of distribution of electrons according to electronic sources: 1s 2 2s 2 2p 4 type of atom 1) chlorine 2) fluorine 3) acidic 4) sirki 2. In a row
VSSEROSIISKA OLIMPIADA SHKOLYARIV Z ХІМІЇ. 2016 2017 account m MUNICIPAL ETAP. 10 KLAS Zavdannya, revisions, evaluation criteria Zagalnye recommendation: as far as in the established consumer goods, the stench is bound to be
ХІМІЯ Chemistry test for grade 8 (test) 1 option 1. How many of the electrons are on the name of the element with the serial number 11? 1) 1 2) 3 3) 8 4) 11 2. For this little one
The bank is up to the industrial attestation of institutions 9 class A1. Budova atom. 1. The charge of the nucleus of the atom in carbon 1) 3 2) 10 3) 12 4) 6 2. The charge of the nucleus of the atom is sodium 1) 23 2) 11 3) 12 4) 4 3. The number of protons in the nucleus
MOSKOVSKA OLIMPIADA SHKOLYARIV W X XIMIS 2016 2017 academic year m. ETAP 10 class 1. To the wider range of speech A, the rush of the range of acidity and B, at the same time, the speech of 3 orange colora was approved. when heated
VSSEROSIISKA OLIMPIADA SHKOLYARIV Z ХІМІЇ. 2017 2018 academic year m SCHKILNY ETAP. 9 KLAS Zavdannya, according to the criteria for evaluating Zavdannya 1. Two gas Two gas X and Y are mutually reconfigured one into one.
Robot trainer from preparation to OGE on ХІМІЇ 13 March 2015 rocky 9th class Option ХІ90403 Viconano: PIB class
Test (solution) Additions 1. A chemical element is a kind of atoms with the same charge of the nucleus. 2. Mole a few words, how to take revenge on the particles of particles, and on the atoms to take place in 12 grams in coal (12
VSSEROSIISKA OLIMPIADA SHKOLYARIV Z ХІМІЇ. 2016 2017 account m SCHKILNY ETAP. 10 KLAS Zavdannya, based on the criteria of assessment
Test for chemistry class 11 (basic level) Test “Typical chemical reactions (class 11 chemistry, basic level) Option 1 1. Concepts for correct reactions and use of type: a) Al 2 O 3 + HCl, b) Na 2 O + 2 O,
System for evaluating rehearsal robots from chemistry. For a new correct display on the skin from the factory 16 19, 2 bali is given; I’m allowed
Introductory notes (26) The same stages of oxidation, such as in P 2 O 5, phosphorus in the bottom 1) PH 3 2) H 3 PO 4. 3) Ca 3 P 2 4) PH4 Cl Chemical element of the 3rd period VA group display scheme
Demonstration version of conversion materials for industrial attestation of class 9 (in the form family education and self-knowledge) according to ХІМІЇ 4 5 В 4 periods of the head group of the V (A) group
Code Part 1 Part 2 С1 С2 С3 С4 С5 С6 Pidsumkovy ball (from 100 points) Introduced to the robot for beginners up to 10 FG and HB class Chastina 1 Circle the number of one correct display with a gurtcomb. If the message is correct
Хімія 11 class. Demonstration option 4 (45 hvili) 1 Diagnostic thematic robot 4 according to the preparation up to ADI from chemistry for the themes “Metals. Nonmetals »Instructions on the Robot Victory On the Robot Victory
C1 Chemistry. 11 class. Option XI1060 1 Criteria for evaluating the plant with a flared view of the Vikorist method of electronic balance, adding an equal reaction: Cu 2 O + = SO 2 + + H 2 O
A short information about the conversion robotics for 9th grade chemistry Reverse robot to be stored in two parts, which include 22 zavdannya. Part 1 to revenge 19 buildings with a short view, part 2 to revenge
Trenuvalny version of examination robots for preparation to DPA for students of 9 grades. Rudnichenko G.N., teacher of chemistry, MOU SZSH 5 Kopeysk district of the Chelyabinsk region
MUNICIPALNE BUDGETNA ZAGALNOOSVITNІY INSTANOVA "KELCHIURSKAYA SECONDARY ZAGALNOOSVITNYA SCHOOL" "KELCHIURSA SHÖR SCHOOL"
UVAGA! PERSONAL DATA OF ABITURINTA The code is NOT included in the clean copy Part 1 Part 2 Part 3 Sum max 50 b clean Copy of the robot from chemistry to the chemistry group of the 9th FG class Part 1. Add
VSSEROSIISKA OLIMPIADA SHKOLYARIV Z ХІМІЇ. 2016 2017 account m MUNICIPAL ETAP. 8 KLAS Zavdannya, revisions, evaluation criteria Zagalnye recommendation: as far as in the established consumer goods, the stench is bound to be
Option 24 Chastina 1. In case of viconanity of the building 1 15, insert only one digit, as it will give the correct number. 1 The number of electrons in the atoms of the road 1 1) the number of protons 2) the number of neutrons 3) the sum
Nutrition before industrial attestation from chemistry in grades 8-9 Pidruchnik G.Ye., Rudzitis, F.G. Feldman "Khimiya 8th class", "Chemistry 9th class" Moscow 2014 1. Periodic law and periodic system chemical elements
Management of B10 from chemistry 1. Mass of acid, necessary for the secondary burning of 67.2 l (n.u.) water up to SO 2, expensive. rorahuvati number
Хімія 8 class. Demonstration option 2 (45 chilines) 1 Diagnostic thematic robot 2 on preparation to OGE on ХІМІЇ for the topics “Basic classes of inorganic spoluk. Genetic link between classes
EXAMINATION TEST S CHIMIS (externate 9 CLAS) 1. Chemistry reaction, against the established siege a) h 2 SO 4 + BaCl 2 b) HNO 3 + KOH c) HCl + CO 2 d) HCl + Ag 2. rechovin a) carbonate
Хімія 9 class. Demonstration option 5 (45 khvili) 1 Diagnostic thematic robot 5 from preparation to the OGE on ХІМІЇ for the topics “Nonmetals IVA VIIA group periodic systems chemistry elements D.I.
Bagatoprofilna Olympiad. 2017/2018 navchalny rik... Moscow Technological University. Conclusions stage. Head of chemistry. 11 cl. Manager 1. Sumіsh three gasіv А, В, С for water transport
Put it on. Basic laws of chemistry. Chemically equivalent. Equivalent Law. Razrakhunki for the formulas The value of the mass and the amount of ammonia NH in the same gas, which is 5 ave, 5 molecules. Decision. molar
VSSEROSIISKA OLIMPIADA SHKOLYARIV Z ХІМІЇ. 2016 2017 account m SCHKILNY ETAP. 9 CLAS Zavdannya, based on the assessment criteria
Chemia. Class 9 Option XІ90501 2 District. Misto (settlements) School. Klas Pryzvische. Ім'я. By Batkovi Trenuvalna robot in DPA format from February 13, 2014 rock 9 class Option XІ90501 Instructions
Option 1 1. Ion XO 2 to revenge 24 electrons. Start a non-homely element and write a simple conversation with a letter. (6 points) Decision. nevidomy element
Grade 8 handlers: Khimiya-8 O.S. Abrielian Teacher Puppet I .. Vivchity paragraphs 1 to 24. Control robot for 1 week in chemistry 8th class Chastina (choose one correct answer): 1. Rozpodil electronic
The amount of speech. Avogadro's number. n = m M n number of words (mol); m mass of speech (g); M molar mass of speech (g / mol) n = N N A N number of molecules; N A = 6.02. 10 23 molecules / mol 1 mol be-like
Хімія 9 class. Demonstration version 5 (90 hvili) 1 Diagnostic thematic robot 5 from preparation to the OGE on ХІМІЇ for the topics “Non-metals IVA VIIA group Periodic systems of chemical elements D.I.